Molarity of a concentrated hydrochloric acid solution?

Well since it's 37% I would multiply it by 100 since we want nice number, that's what my chem book said that one would do in such a situation. So because of that we would get 37 grams. Then we solve for mL and get 33mL which would ve 0.033 L. Then take the 37 grams and divide by the formula weight of hydrochloric acid which is 37.47. We would get .9875 mol and then we would divide the mol by the liters and get 29.92 M <----- molarity.